Answer:
A = 53.34
![units ^ 2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/mwc7v36qhrmtcj4qepnnemki5xjccz2xoi.png)
Explanation:
To find the length of the rectangle we solve the PLA triangle
Using the Pythagorean theorem we find the PL side.
![PL = √(4^2+12^2)\\PL = √(16+144)\\PL = 12.65](https://img.qammunity.org/2019/formulas/mathematics/middle-school/668lyulwp4u9yysqj7i46lxyx34xi79a4z.png)
Then the length of the rectangle is 12.65
Now we solve the MALU triangle. Where MU = PL
We use the Pythagorean theorem:
![MU^2+LU^2 = (MA + AL)^2\\12.65^2+LU^2 = (MA+12)^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/k80p8u14pxbsgdhvhh1nje77syeyx4v07o.png)
Where LU and MA are unknown.
Finally we solve the triangle MPA
![MA^2 + PA^2 = PM ^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9e16hhn0l347kwgkirk7boye2v6nc8qd6g.png)
Where PM = LU
So:
![MA^2 + 4^2 = LU^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/1nr4gwkn8iz66q1ewk3u5t6h1gkse8vthh.png)
Now we have two equations and two unknowns. So we solve the system.
(i)
(ii)
We introduce (ii) in (i)
![12.65^2 + MA^2+16=MA^2+24MA+144](https://img.qammunity.org/2019/formulas/mathematics/middle-school/eoupbbaf7bgw2hzgo779xp5fxi0t6q1wvq.png)
Now we clear MA
![160.02+16-1 44 = 24MA](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5cv48hs63uljmux48y3msn72hesv32uhxr.png)
![32.02 = 24MA](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ty49cubnog3p8r127ldbrkg50sv9gi9aaz.png)
![MA = (32.02)/(24)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/qkkkqhumzykebx2r7u3t25nsap90x2eygx.png)
MA = 1.3342 (iii)
Now we introduce (iii) in (ii)
1.3342^2 + 4^2 = LU^2
LU = 4.2166
Now we have the length of the rectangle and also its width.
The area A of a rectangle is:
A = l*w
Where
l = length
w = width
A = 4.2166*12.65
A = 53.34
![units^2](https://img.qammunity.org/2019/formulas/mathematics/middle-school/122x8pxmialzq328axbvpd9r49n4hd4b5c.png)