Answer:
2,000 problems
Explanation:
We know the students solved the following amount of problems:
Week 1 - 25% of the month
Week 2 - 110% of the first week--> this means 25(1.10)=27.5%
Week 3 - 60% of the first two week--> this means 0.6(25+26.5)=31.5%
Week 4 - 320 problems --> this is 16% of the quota since 100-25-27.5-31.5=16%
So we know that 320 is 16%. We can set up a proportion to find the total amount.

We solve by cross multiplying by multiplying numerator and denominator on opposite fractions.

The quota for the month is 2,000 problems.