Question

what is the net force of a 6 kg object that goes from a velocity of 0.5 m/s to a velocity of 3 m/s over the course of 1.5 seconds? PLEASE ANSWER ASAP I HAVE 10 MINUTES PLEASEEEEEE

Answer 1

∑F = 10.2 N

Step-by-step explanation:

We have:

Initial velocity: 0.5 m/s

Final velocity: 3 m/s

Time: 1.5 s

We have all of the components needed to calculate acceleration. Let's do that, shall we?

a = vf-vo/t

a = 2.5/1.5

a = 1.7
`m`/
`s^(2)`

Now, look at the Net Force equation:

∑F = ma

Plug in the variables, to get:

∑F = (6)(1.7)

∑F = 10.2 N (You can round this according to significant digits)