Question

In the triangle below, what is cos B?

Answer 1

cos B = c/a

cosine is adjacent over hypotenuse.


there is an acronym for this: soh-cah-toa

soh: sine is opposite over hypotenuse
cah: cosine is adjacent over hypotenuse
toa: tangent is opposite over adjacent

Answer 2

`\text{cos}(B)=(c)/(a)`

Explanation:

We have been given a triangle. We are asked to find
`\text{cos}(B)`.

We know that cosine relates adjacent side of a right triangle to its hypotenuse.

`\text{cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}`

We can see that side AB is adjacent side and CB is hypotenuse of our given right triangle.

`\text{cos}(B)=(AB)/(CB)`

`\text{cos}(B)=(c)/(a)`

Therefore, our required value is
`\text{cos}(B)=(c)/(a)`