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How many grams of product are formed from 2.0 mol of N2 (g) and 8.0 mol of Mg(s)? Show all calculations leading to an answer. List 3 indicators of a chemical change.

User Chani
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1 Answer

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Balanced chemical reaction happening here is:

3Mg(s) + N₂(g) → Mg₃N₂(s)


moles of product formed from each reactant:


2.0 mol of N2 (g) x 1 mol Mg₃N₂ = 2 mol Mg₃N₂

1 mol N2

and


8.0 mol of Mg(s) x 1 mol Mg₃N₂ = 2.67 mol Mg₃N₂

3 mol Mg


Since N2 is giving the least amount of product(Mg₃N₂) ie. 2 mol Mg₃N₂

N2 is the limiting reactant here and Mg is excess reactant.


Hence mole of product formed here is 2 mol Mg₃N₂


molar mass of Mg₃N₂

= 3 Mg + 2 N

= 101g/mol


mass of product(Mg₃N₂) formed

= moles x Molar mass

= 2 x 101

= 202g Mg₃N₂


202g of product are formed from 2.0 mol of N2(g) and 8.0 mol of Mg(s).


The following are indicators of chemical changes:

Change in Temperature

Change in Color

Formation of a Precipitate



User Nitin Kumar
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