Question

A man gave each of 2 sons 1/3 of his herd of cows and sold 1/5 of the herd. What part of the head is left

Answer 1

Answer:
`\frac2{15}`

Explanation:

Given: Part of herd each son got =
`\frac13`

Part of son 2 sons got =
`2*\frac13=\frac13`

Part of herd sold =
`\frac15`

Then, part of the herd is left =
`1-(2)/(3)-\frac15` [ Consider whole part as 1.]

`=(15-10-3)/(15)\\\\=(2)/(15)`

Hence, part of the herd is left =
`\frac2{15}`