Question

For questions 4 – 7, answer the questions about secant-secant angles.

Answer 1

4). m∠DAE = 23°

5). m(∠BAE) = 29.5°

Explanation:

4). "Angle formed by the intersection of two tangents and secants outside the circle is half of the difference of intercepted arcs"

m∠DAE =
`(1)/(2)(62-16)`

=
`(46)/(2)`

= 23°

5). Following the same rule as in question 4,

m(∠BAE) =
`(1)/(2) [m(\text{arc BE})-m(\text{arc CD})]`

=
`(1)/(2)(88-29)`

=
`(59)/(2)`

= 29.5°