Question

Pls explain why

two cars start a trip of 200 km at the same time. the first car travels at 90 km/h and the second at 110 km/h. how much more time in minutes does it take for the slower car to reach its destination?

Answer 1

The slower car takes 24 more minutes to reach its destination.

Step-by-step explanation:

Constant speed motion

An object moves at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

`\displaystyle v=(d)/(t)`

Where

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

`\displaystyle t=(d)/(v)`

Two cars move at different speeds and must travel a distance of d=110 km. The first car travels at v=90km/h. It takes a time of:

`\displaystyle t_1=(200)/(90)=2.22\ h`

Converting to minutes:

`t_1=2.22*60= 133\ min`

The second car travels at v=110km/h. It takes a time of:

`\displaystyle t_2=(200)/(110)=1.82\ h`

Converting to minutes:

`t_2=1.82*60= 109\ min`

The slower car takes 133 - 109 = 24 more minutes to reach its destination.