141k views
1 vote
Hayk was walking around the cross-shaped pool with 10m-long sides , while Karlen was swimming in it. During the time Hayk got from point A to point B, Karlen swam diagonally from point B to A and back.

By what percent did the distance covered by Karlen exceed that of Hayk ? (round your answer to the nearest tenth)

Hayk was walking around the cross-shaped pool with 10m-long sides , while Karlen was-example-1
User SamJolly
by
8.6k points

1 Answer

5 votes

Answer:

5,41%

Explanation:

Remark

It's hard to interpret what % increase means. I'm going to work first with the actual increase and then I'll give the % increase. The answer I give will likely be in your choices, but it could still be incorrect.

Givens

Walking distance from A to B = 10 units down + 10 units east + 10 units down + 10 units east + 10 units down + 10 units east = 60 units.

Swimming distance = 2*sqrt(10^2 + 30^2) = 63.25 units.

Solution

The difference = 63.25 - 60 = 3.25

The % increase = (3.25/60)*100 = 5.41%

User Jess Telford
by
7.7k points