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In the pully system shown in this figure, MQ = 10 in, NP = 3in and QP=24in. Find MN

a. 25
b. 26
c. 27
d. 28

In the pully system shown in this figure, MQ = 10 in, NP = 3in and QP=24in. Find MN-example-1
User Plaxdan
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1 Answer

3 votes

Answer:

The correct option is a. The length of MN is 25.

Explanation:

Given information: MQ = 10 in, NP = 3 in and QP=24 in.

If the centers of two circles of radius r₁ and r₂ are d units apart, then the length of the direct common tangent between them is


l=√(d^2-(r_1-r_2)^2)


24=√(d^2-(10-3)^2)

Square both sides.


576=d^2-49


625=d^2

Take square root both sides.


25=d

Therefore length of MN is 25 and option a is correct.

User AhmadReza Payan
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