1. Area of the original patio: 35 ft^2
The original patio has is a rectangle with length = 7 feet and width = 5 feet. The area of a rectangle is given by the product between length and width:
![A=L \cdot W](https://img.qammunity.org/2019/formulas/mathematics/college/vrgkzgei6uxjmb9u1dxj844fa5pcaunltt.png)
Therefore, since in this case L=7 and W=5, the area of the original patio is
![A=(7 ft)(5 ft)=35 ft^2](https://img.qammunity.org/2019/formulas/mathematics/college/yw83y0dh7jggzubwml9l86277lgsuigbc7.png)
2. Area of section A: 7x ft^2
Section A is also a rectangle, with length = 7 feet and width = x. Therefore, the area of this section is equal to:
![A=L\cdot W=(7 feet)(x)=7x](https://img.qammunity.org/2019/formulas/mathematics/college/vw4nyvdcrdu6fmyff5o81h2iwp6ep74luc.png)
3. Area of section B: 5x ft^2
Section B is also a rectangle, with length = x and width = 5 feet. Therefore, the area of this section is equal to:
![A=L\cdot W=(x)(5 feet)=5x](https://img.qammunity.org/2019/formulas/mathematics/college/gin9n2v6aedz3x5f5ztjpn6vq97te7c159.png)
4. Area of section C:
![x^2 ft^2](https://img.qammunity.org/2019/formulas/mathematics/college/ev053pmcuynwzhggavpws9h370yy2tcwh3.png)
Section C is a square, with side equal to x. The area of a square is equal to the square of the length of the side:
![A=L^2](https://img.qammunity.org/2019/formulas/mathematics/college/ffnnwxa1wy9lx0f2lman87qy3q6wu775m0.png)
therefore, in this case, since L = x, the area of this section is
![A=(x)^2 = x^2](https://img.qammunity.org/2019/formulas/mathematics/college/se47t5qoh05nik3i2lgwlwla9omf6c90o7.png)
5. Total area of the new patio using addition:
ft^2
The total area of the new patio is equal to the sum of the four areas calculated in the previous sections:
ft^2
6. Total area of the new patio using multiplication:
![x^2+12x+35](https://img.qammunity.org/2019/formulas/mathematics/college/god9rqrbs7nq2no38ebgc3hegqlnmuv8dd.png)
The total area of the new patio is equal to the product between the length (7+x) and the width (5+x):
ft^2
7. Yes
As we can see by comparing the area calculated in 5. and the area calculated in 6., the two areas are equal.
8. 80 ft^2
We already have the formula for the area of the new patio:
![A=x^2+12x+35](https://img.qammunity.org/2019/formulas/mathematics/college/6xeowrze5qsns3kk46j5c8dnzbbuozmf9h.png)
If we substitute x=3, we find the value of the area:
![A=(3)^2+12\cdot 3+35=9+36+35=80](https://img.qammunity.org/2019/formulas/mathematics/college/e69hw1puy2msscnbrvkxdy9hzk9kpo0hpb.png)