ANSWER
![11.29 \: hours](https://img.qammunity.org/2019/formulas/mathematics/high-school/m3it8k1o63cg5xdszv0dvk46hnxw9h111p.png)
EXPLANATION
The exponential function that models cell duplication in the lab is given as
![f(t) = {2}^(t + 2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/wswsvgg6yfzk61vs38kkqbuscvv5hoqop4.png)
We want to determine the time it will take for the cells to increase to
![10,000.](https://img.qammunity.org/2019/formulas/mathematics/high-school/h1oze8ex4i1fgj0eddobe2y90167fqtfkk.png)
In other words, we want to find the value of
![t](https://img.qammunity.org/2019/formulas/mathematics/college/wn85rs21zjpgno6qvvr81v18j25hkod1uk.png)
when
![f(t) = 10,000](https://img.qammunity.org/2019/formulas/mathematics/high-school/zwwnykmmv3egdacvaz8g4il5o5uud0mb0h.png)
This gives us the equation,
![10,000 = {2}^(t + 2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/jjqrlbvjeck36l4r7h852qqq3z7gfegz80.png)
Recall that,
![{a}^(m + n) = {a}^(m) * {a}^(n)](https://img.qammunity.org/2019/formulas/mathematics/high-school/xf5yw7wpuyff2vv0bx2ht24ak4mc0xn7an.png)
We apply this property to the right hand side to obtain,
![10,000 = {2}^(t) * {2}^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/6unl8b53bo51gy1wadrlb41xsrnlvolso7.png)
This implies that,
![10,000 =4 * {2}^(t)](https://img.qammunity.org/2019/formulas/mathematics/high-school/kpakxagsrfantfg671t9ll3kvt57qnlsze.png)
We divide both sides by 4 to get,
![2500 = {2}^(t)](https://img.qammunity.org/2019/formulas/mathematics/high-school/t9djxkn4xkf98bk2f4ym2vm4r3ohqd3t0q.png)
We take the antilogarithm of both sides to base 10 to get,
![t = log_(2)(2500)](https://img.qammunity.org/2019/formulas/mathematics/high-school/3h02vj6umh479olh0fn4skfthtwbs7nwdr.png)
This implies that,
![t = 11.29 \: hours](https://img.qammunity.org/2019/formulas/mathematics/high-school/ghq2vo8pnrbxktccfyp3xt9nwtxxt61wxi.png)
to the nearest hundredth.