Question

Let f(x)=−0.5(x−8)^2−2 .

What is the average rate of change for the quadratic function from x=−4 to x = 8?



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Please help, thank you

Answer 1

Let f(x)=−0.5(x−8)2−2.

What is the average rate of change for the quadratic function from x=−4 to x = 8?

Enter your answer in the box.

Answer is 6 too the test

Explanation:

Answer 2

2

Explanation:

`f(x)=-0.5(x-8)^2-2`

Average rate of change formula is

`Average = (f(x_2)-f(x_1))/(x_2 - x_1)`

Here x1=-4 and x2= 8

Lets find f(x1) and f(x2)

`f(x)=-0.5(x-8)^2-2`

`f(-4)=-0.5(-4-8)^2-2=-74`

`f(8)=-0.5(8-8)^2-2=-2`

now we plug in all the values in the formula

`Average = (f(x_2)-f(x_1))/(x_2 - x_1)`

`Average = (-2-(-74))/(8-(-4))`

`Average = (72)/(12)=6`

Average rate of change = 6