Explanation:
To find the right matrix, you have to look which matrix among the options has doubled each item.
For example, if you have:
![\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]](https://img.qammunity.org/2019/formulas/mathematics/college/3jodboogts3eue30u6d35j1u9nmlz0b92x.png)
Then, your answer would be:
![\left[\begin{array}{ccc}2&4&6\\8&10&12\\14&16&18\end{array}\right]](https://img.qammunity.org/2019/formulas/mathematics/high-school/pk8zjqowvb9ck5axionb79ad4zfj1ioue7.png)
Because each term is the double of the original matrix.
Remember that, this operation is between a scalar and a matrix. That operation is done according to this property:
![aM=a\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] = \left[\begin{array}{ccc}1a&2a&3a\\4a&5a&6a\\7a&8a&9a\end{array}\right]](https://img.qammunity.org/2019/formulas/mathematics/high-school/1vz226f9e6sdyd0zkxv4isfpedmqk7i9v2.png)
In fewer words, the scalar will multiply each element of the matrix.