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What is the solution to this system of linear equations? X-3y=-2 and x-3y=16

User Fjlksahfob
by
8.4k points

2 Answers

6 votes

Answer:

NO SOLUTION

Explanation:

Two equations of the system of linear equations has been given as x - 3y = -2 and x - 3y = 16

if we see in these equations slopes are same for both.

x - 3y = -2

+3y = +2 +x

y =
(1)/(3)x +
(2)/(3)

slope m₁ =
(1)/(3)

x - 3y = 16

-3y = 16-x

3y = x - 16

y =
(1)/(3)x -
(16)/(3)

slope m₂ =
(1)/(3)

so m₁ = m₂ =
(1)/(3)

These lines are parallel to each other.

Since parallel lines don't intersect each other so there is NO SOLUTION for this system of equation.

User Cristiano Sousa
by
8.7k points
0 votes

Answer:

No solution

Explanation:

Equations:

x - 3y = -2

x - 3y = 16

Subtract:

0 - 0 = -18

Answer:

No solution

User Dantz
by
8.1k points

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