Question

Calculate the kinetic energy, in J/mole, of 1.00 mole of gaseous water molecules at room temperature (25.0ºC).

Answer 1

Kinetic energy is 100 because it is at room temperature

Answer 2

Answer : The kinetic energy is,
`3.716* 10^(3)J/mol`

Explanation :

The formula for kinetic energy is:

`K.E=(3)/(2)RT`

where,

R = gas constant = 8.314 J/mol.K

T = temperature =
`25.0^oC=273+25.0=298.0K`

Now put all the given values in the above kinetic energy formula, we get:

`K.E=(3)/(2)* (8.314J/mol.K)* (298.0K)`

`K.E=3.716* 10^(3)J/mol`

Therefore, the kinetic energy is,
`3.716* 10^(3)J/mol`