Question

ASAP

In chickens, rose comb (R) is dominant over single comb (r). When a heterozygous rose-combed rooster is mated with a single-combed hen, what is the expected phenotypic ratio of the offspring?

Answer 1

The expected phenotypic ratio of the offspring would be

75% rose comb

AND

25% single comb

Answer 2

In this offspring, both rose comb and single comb can be expected.

Creating a punnet square will show this with Rr (Heterozygous) being on top and rr (homozygous) being on the left side. When put into the punnet square, it shows a 50/50 chance for both results with two homozygous chances of rr and two heterozygous chances of Rr.

Therefore, the phenotypic ratio of the offspring would be 2:2 or 50/50 as both have an equal chance.

Hope this helps!