Question

A unit that is equal to 33 000 ft-lbs/min or 550 ft-lbs/s is the

watts

kilograms

joules

horsepower



You are a nurse in a hospital. You are told to move a patient through three corridors each measuring 14.33 meters. Because of friction it requires a constant force of 848 N to move the patient and wheelchair. How much work must you perform to accomplish this task?

A-34,512 N
b-6,221 N
c-973 N
d- 456.5 N
e- 36,456 N

If you managed to accomplish the task of wheeling your patient down the three hospital corridors in 5 minutes, what was your average velocity while doing so?

71.65 m/s

0.34 m/s

13.5 m/s

0.14 m/s

You buy a whirling toy helicopter for your little brother that is attached to a thin, flexible wire that the operator holds as the helicopter spins around the operator. If the length of the wire is 0.6 m and the tangential velocity of the toy helicopter is 0.57 m/s what is the helicopter's centripetal acceleration?

0.33 m/s^2

0.67 m/s^2

0.54 m/s^2

83.20 m/ft^2

30 mm/s^2

A cog on a gear spins around the gear's axis. If the gear's radius is 3.79 meters and it takes the cog 0.51 minutes to complete a full rotation, what is the cog's tangential speed?

46.67 m/min

34 m/sec

3.79 mi/min

1.25 m/sec

12 m/min

A cog or a cut tooth on a gear spins around the gear's axis. If the gear's radius is 3.79 meters, what distance does the cog travel around a gear's rotation?
3.79 m

12.9 m

34.12 m

1.25 m

23.8 m

How much power would be required to raise a 50 kg sack of flour from the floor to a table one meter high in 2 seconds? (g=9.81 m/s^2)

345 N*m
245 Watts
981 Watts
364 N*m
622 Watts

Answer 1

1.

Answer:

Horsepower

Step-by-step explanation:

As we know that "lb" is the unit of force

"ft" is the unit of distance

so here it is "ft-lb/ s" so it is product of force and distance and then divided by time

so it is work done per unit time which is power

so unit of power is given by Horsepower

2.

Answer:

The work done is 36456 J

Step-by-step explanation:

Length of each corridor = 14.33 m

total distance moved in three corridors = 3(14.33) = 42.99 m

Force applied = 848 N

So work done to move through the corridors is given as

`W = F.d`

`W = 848 * 43 = 36456 J`

3.

Answer:

The velocity will be 0.14 m/s

Explanation

Average velocity is the ratio of total distance and total time.

Here total distance moved in three corridors will be

`d = 42.99 m`

total time is given as

`t = 5* 60 = 300 s`

so average velocity will be

`v = (42.99)/(300) = 0.14 m/s`

4.

Answer:

Centripetal acceleration = 0.54 m/s^2

Step-by-step explanation:

As we know that centripetal acceleration is given as

`a_c = (v^2)/(R)`

now we have

`v = 0.57 m/s`

`R = 0.6 m`

now we have

`a_c = (0.57^2)/(0.6) = 0.54 m/s^2`

5.

Answer:

The answer is 46.67 m/min

Explanation:

As we know that tangential speed is given by

`v = (2\pi r)/(t)`

here we have

`r = 3.79 m`

`t = 0.51 min`

now we have

`v = (2\pi(3.79))/(0.51)`

`v = 46.47 m/min`

6.

Answer:

Distance traveled = 23.8 m

Step-by-step explanation:

As we know that distance traveled in one complete revolution is given as

`d = 2\pi r`

`d = 2\pi(3.79)`

`d = 23.8 m`

so distance traveled will be 23.8 m

7.

Answer:

Power = 245 Watts

Step-by-step explanation:

As we know that power is defined as rate of work done

so we will have

`P = (W)/(t)`

here we have

`W = mgh`

now we will put all the values in it

`P = (50(9.81)(1))/(2)`

`P = 245 Watt`

Answer 2

Answer to Q1:

A unit that is equal to 33 000 ft-lbs/min or 550 ft-lbs/s is the horsepower

Step-by-step explanation:

Prefix or symbol for horsepower is: hp

Prefix or symbol for foot pound per minute is: ft-lb/min.

One horsepower converted into foot pound per minute equals = 33,000.00 ft-lb/min

1 hp = 33,000.00 ft-lb/min

So horsepower is the correct answer

Answer to Q2:

The work done is 36456 J

Explanation:

Length of corridor = 14.33 m

Length of 3 corridors = 14.33 x 3 = 42.99

And,

Force = 848

As we know Work = Force x Displacement

Work = 848 x 42.99 = 36456 J

Answer to Q3:

The velocity will be 0.14 m/s

Explanation:

Since the length is given as 42.00 in the previous questions so we will use the same length

Now the time given is 5 minutes which is equal to 300 seconds

As we know velocity = distance / time

Velocity = 42.99 / 300

Velocity = 0.14 m/s

Answer to Q4:

Centripetal acceleration = 0.54 m/s^2

Explanation:

The centripetal acceleration is given by V^2 / r

So centripetal acceleration = 0.57 / 0.6

Centripetal acceleration = 0.54 m/s^2

Therefore 0.54 is the correct answer

Answer to Q5

The answer is 46.67 m/min

Explanation:

From the question statement we observe that

r=3.79 m and t=.51 min

We have to find distance covered by a cog which is equal to the circumference of gears rotation.

d=2πr

d=2π(3.79)

d=23.8 m

so putting the values of d and t in the velocity formula we get

v=23.8/.51

v=46.67 m/min which is the answer.

Answer to Q 6

The answer is 23.8 m

Step-by-step explanation:

From the question statement, we observe that

r=3.79 m

The distance is equal to the circumference of gears rotation.

So, the formula for distance is d=2πr

d=2π(3.79)

d=23.8 m which is the correct answer

Answer to Q 7

Power = 245 Watts

Explanation:

The power formula is

P = Work / time

Here work = potential energy

Potential Energy = mgh

So

Power = mgh / time

Power = 50 x 9.8 x 1 and divided by 2

Power = 490 / 2

Power = 245 Watts