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(a) Let p represent the proportion of all supermarket shoppers who always stock up on an item when they find a real bargain. Find a point estimate for p. (Enter a number. Round your answer to four decimal places.)

1 Answer

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Here \ is \ the \ missing \ part.


In \ a \ marketing \ survey, \ a \ random \ sample \ of \ 992 \ supermarket \ \ shoppers \ \ revealed


that \ 274 \ always \ stoc k \ up \ on \ a n \ item \ when \ they \ find \ that \ item \ at \ a \ real \ bargain \ price.

Answer:

0.2762

Explanation:

The point estimate is the best guess of the true parameter. It is an estimate of a population parameter and it is a single value of statistics.

The sample proportion
\hat p is the point estimate of the population proportion p

Given that

The sample mean = 274; &

The sample size = 992

Then,

The point estimate
p = (x)/(n)


p = (274)/(992)

p = 0.2762

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