Answer:
The distance from the center of the target to the point where the bullet strikes the target is 0.31 m.
Step-by-step explanation:
Given;
the position of center of the target, x₀ = 60 m
initial velocity of the bullet, u = 240 m/s
The time the bullet strikes the center of the large target is calculated as;
![t = (x_o)/(u) =(60)/(240) = 0.25 \ s](https://img.qammunity.org/2022/formulas/physics/college/l9pur3xfoxkfvnwsf6lbvg0jpgd5wav1eu.png)
The distance from the center of the target to the point where the bullet strikes the target is calculated as;
x = vt + ¹/₂gt²
where;
v is the final velocity of the bullet when it strikes the target = 0
x = 0 + ¹/₂(9.8)(0.25²)
x = 0.31 m
Therefore, the distance from the center of the target to the point where the bullet strikes the target is 0.31 m.