Question

Identify the equation in point-slope form for the perpendicular bisector of the segment with endpoints B(−1,1) and C(−5,−7). PLEASE HELP!!!

Answer 1

Equation in point-slope form=
`{y+3}=(-1)/(2)(x+3)`

Explanation:

The given end points are B(−1,1) and C(−5,−7)

Mid point M of BC=
`(-5-1)/(2)` ,
`(-7+1)/(2)`

Mid point M of BC = -3 , -3

Slope of BC =
`(-7-1)/(-5+1)` = 2

Slope of bisector= m=
`(-1)/(2)`

Equation of perpendicular bisector :
`(y+3)/(x+3)=(-1)/(2)`

⇒
`{y+3}=(-1)/(2)(x+3)`

⇒ 2(y+3)= -(x+3)

⇒
`2y+x=-9`