Question

PLEASE SHOW WORK and inlcude units on each number

Sulfuric acid reacts with sodium hydroxide.


If 3.50 mol H2SO4 is made to react with 10.0 mol NaOH, identify the limiting reagent. First write the balanced equation, then do the calculations. Show all work!

Answer 1

The limiting reagent is H₂SO₄

calculation

Step 1 :write the equation for reaction

2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

Step 2: use the mole ratio to determine the moles of product produced from each reactant

that is from equation above,

NaOH : Na₂SO₄ is 2 :1 therefore the moles of Na₂So₄

= 10.0 moles x 1/2 = 5.0 moles

H₂SO₄ :Na₂SO₄ is 1:1 therefore the moles of Na₂SO₄ is also = 3.50 moles

H₂SO₄ is the limiting reagent since it produces less amount of Na₂SO₄