Answer:
The distance from he ball to the goal is 11.85 feet (Approx) .
Explanation:
As given
The angle of elevation from a soccer ball on the ground to the top of the goal is 34° .
If the goal is 8 feet tall.
Now by using the trigonometric identity .
![tan \theta = (Perpendicular)/(Base)](https://img.qammunity.org/2019/formulas/mathematics/high-school/c8ef501ikskaw2kikr3fvrj6quqh18jx2z.png)
As shown in the diagram given below
![\theta = 34^(\circ)](https://img.qammunity.org/2019/formulas/mathematics/college/ghh9pay4sxthf43a0o17aytgv09m4ql1kh.png)
Perpendicular = AB = 8 feet
Base = BC
Put all the values in the identity .
![tan\ 34^(\circ) = (AB)/(BC)](https://img.qammunity.org/2019/formulas/mathematics/college/x31rd3nnnwb6mnmldeclojrfh0l8l4zb91.png)
![tan\ 34^(\circ) = (8)/(BC)](https://img.qammunity.org/2019/formulas/mathematics/college/myttnsrbc86nh8qz3mfbilirtjq95rs2od.png)
![tan\ 34^(\circ) = 0.675\ (Approx)](https://img.qammunity.org/2019/formulas/mathematics/college/3a6w4c2kxm25gl7orv1sw8o2vleqe21c89.png)
![BC = (8)/(0.675)](https://img.qammunity.org/2019/formulas/mathematics/college/z1h25zu5e1av80fykn98bbjk86avb182iu.png)
BC = 11.85 feet (Approx)
Therefore the distance from he ball to the goal is 11.85 feet (Approx) .