Question

What is the slope of a line perpendicular to the line whose equation is x - 3y = -18. Fully reduce your answer.​

Answer 1

Given:

Equation of a line is

`x-3y=-18`

To find:

The slope of the line perpendicular to the given line.

Solution:

The slope of the equation
`ax+by=c` is

`Slope=-(a)/(b)`

We have,

`x-3y=-18`

Here, a=1, b=-3. So, slope of this line is

`m_1=-(1)/(-3)`

`m_1=(1)/(3)`

Product of slopes of two perpendicular lines is -1.

Let slope of perpendicular line is
`m_2`.

`m_1\cdot m_2=-1`

`(1)/(3)\cdot m_2=-1`

`m_2=-3`

Therefore, the slope of the perpendicular line is -3.