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Write equations for the reaction of the zwitterion of the amino acid glycine with HCl and with NaOH.

User Rastik
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Final answer:

The zwitterion of glycine reacts with HCl and NaOH to form different ions. With HCl, a positively charged ion is formed as glycine accepts a proton. With NaOH, a negatively charged ion results as glycine donates a proton.

Step-by-step explanation:

The reaction of the zwitterion of glycine with HCl and NaOH can be represented by two different equations. In the presence of HCl, the amino group (–NH2) of the zwitterion will act as a base and accept a proton, forming a positively charged ion. Conversely, when glycine reacts with NaOH, the carboxylic acid group (–COOH) will lose a proton, which results in a negatively charged ion.

The equation for the reaction of the zwitterion of glycine with HCl is:

NH3+CH2COO− (zwitterion) + HCl → NH3+CH2COOH + Cl−

The equation for the reaction of the zwitterion of glycine with NaOH is:

NH3+CH2COO− (zwitterion) + NaOH → NH2CH2COO− + H2O + Na+

In the first equation, glycine acts as a base accepting a proton, while in the second it acts as an acid donating a proton. These reactions are typical for amino acids, which can function as both acids and bases.

User Rafael Kassner
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Answer: coco channel
User Caleb Gates
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