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The first discount on a camera was 18%. The second discount was 20%. After these two discounts the price was $328. What was the original price?

2 Answers

5 votes

Answer:

$500

Step-by-step explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

Second Discount

20% off means we paid 80%. We know we paid $328 of some price.

I can now cross-multiply by multiplying numerator and denominator from each ratio.

I now solve for y by dividing by 80.

y=410

The price after the first discount was $410.

First Discount We will repeat the steps above with $410. 18% off means we paid 82%.

I can now cross-multiply by multiplying numerator and denominator from each ratio.

I now solve for y by dividing by 82.

y=500

The original price was $500.

User Hetal Vora
by
5.7k points
3 votes

Answer:

$500

Explanation:

We can find the original price of the camera through a proportion. A proportion is an equation where two ratios or fractions are equal. The ratios or fractions compare like quantities.

Second Discount

20% off means we paid 80%. We know we paid $328 of some price.


(80)/(100) =(328)/(y) \\

I can now cross-multiply by multiplying numerator and denominator from each ratio.


80y=100(328)\\80y=32800

I now solve for y by dividing by 80.


(80y)/(80) =(32800)/(80)

y=410

The price after the first discount was $410.

First Discount

We will repeat the steps above with $410. 18% off means we paid 82%.


(82)/(100)=(410)/(y)

I can now cross-multiply by multiplying numerator and denominator from each ratio.


82y=100(410)\\82y=41000

I now solve for y by dividing by 82.


(82y)/(82) =(41000)/(82)

y=500

The original price was $500.

User Roob
by
5.2k points