Question

Picture is shown above
suppose that y varies directly with x, and y=12 when x=15​

Answer 1

y is directly proportional to x

y=kx, where k is a constant

Now, y=12 when x=15

`12 = k * 15 \\ k = (12)/(15) \\ \boxed{k = 0.8}`

When x=2,

`y = 0.8 * 2 \\ \boxed{y = 1.6}`

Equation: y=kx

y: 1.6

Answer 2

Explanation:

Since y is directly proportional to x,

we have y = kx, where k is a real constant.

When x = 15, y = 12.

=> (12) = k(15), k = 0.8.

Therefore we have y = 0.8x.

When x = 2, y = 0.8(2) = 1.6.

The answer is y = 1.6 when x = 2.