Question

If a series circuit contains a 12-V battery, a 6-ohm resistor, and a 4-ohm resistor, what is the current in the circuit?

Answer 1

Answer: 1.2 amps

Step-by-step explanation:

i got it right in my exam :D

Answer 2

In a series circuit the total current is the same throughout resistors and so:

`I_(total)=I_1=I_2`

The voltage is distributed throughout the resistors and so:

`V_(total)=V_1+V_2`

and the total resistance can be calculated by adding up the resistors resistance:

`R_(total)=R_1+R_2`

First thing is to calculate the total resistance and so:

`R_(total)=6\Omega + 4\Omega = 10\Omega`

And by Omh's law V=IR we have:

`V_(total)=I_(total)R_(total)\\\\I_(total)=(V_(total))/(R_(total))= (12V)/(10\Omega) =1.2A`

And so the total current of the circuit is 1.2 amps i.e. 1.2 A.