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A box weighing 46 newtons rests on an incline that makes an angle of 25° with the horizontal. What is the magnitude of the component of the box’s weight perpendicular to the incline?.
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A box weighing 46 newtons rests on an incline that makes an angle of 25° with the horizontal. What is the magnitude of the component of the box’s weight perpendicular to the incline?.

User SpeedOfRound
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1 Answer

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Answer and Explanation :

The magnitude of the component of the box’s weight perpendicular to the incline can be solved using the formula:

F = w cos(a)

Where F is the box’s weight perpendicular to the incline

W is the weight of the box

A is the angle of the incline

F = (46)cos(25)

F = 42 N

User Malik Bilal
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