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3 votes
10 points!!! What is sqr root 12x^8/ sqr root 3x^2 in simplest form

User Breanna
by
5.8k points

2 Answers

4 votes

Answer:

2x^3

Explanation:


(√(12x^8))/(√(3x^2))

Both top and bottom have square root . We can take square root in common


\sqrt{(12x^8)/(3x^2) }

simplify the exponent using exponential property

a^m / a^n = a^{m-n}, subtract the exponents


\sqrt{(12x^8)/(3x^2) }


√(4x^6)


√(4) =2


√(x^6) =√(x^2 \cdot x^2 \cdot x^2) =x^3


√(4x^6)=2x^3

User Cement
by
6.0k points
5 votes

Answer:

2 x^3

Explanation:

sqrt(12 x^8)/ sqrt(3x^2)

combine into 1 term

sqrt(12x^8/3x^2)

when dividing exponents with the same base, we subtract

sqrt(12/3 x^(8-2))

sqrt(4 x^6)

sqrt(4) sqrt(x^6)

2 x^3

User Eugene V
by
7.5k points
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