11.9k views
3 votes
Solve (v-2)^2-27=0 where v is a real number. simplify your answer as much as possible

User Ken Ray
by
9.1k points

2 Answers

2 votes

Steps:

So firstly, add both sides by 27:


(v-2)^2=27

Next, square root both sides of the equation:


v-2=\pm √(27)

Now, we are going to simplify the radical. To do this, we will apply the product rule of radicals which states that
√(ab)=√(a)*√(b) . In this case:


√(27)=√(9)*√(3)=3√(3)\\\\v-2=\pm\ 3√(3)

Lastly, add both sides by 2:


v=2\pm 3√(3)

Answer:

In exact form, your answer is
v=2\pm 3√(3)

User Kthakore
by
7.4k points
2 votes

Answer:

v = 2 ± 3 sqrt(3)

Explanation:

(v-2)^2-27=0

add 27 to each side

(v-2)^2-27+27=0+27

(v-2)^2 = 27

take the square root of each side , remember to take the positive and negative

sqrt((v-2)^2) = ± sqrt27

v-2 = ± sqrt27

add 2 to each side

v-2+2 = 2 ± sqrt27

v = 2 ± sqrt27

we can simplify the square root of 27

sqrt(27) = sqrt(9) * sqrt(3)

sqrt(27) = 3sqrt(3)

v = 2 ± 3 sqrt(3)


User Sterling Nichols
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories