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Solve (v-2)^2-27=0 where v is a real number. simplify your answer as much as possible

User Ken Ray
by
6.8k points

2 Answers

2 votes

Steps:

So firstly, add both sides by 27:


(v-2)^2=27

Next, square root both sides of the equation:


v-2=\pm √(27)

Now, we are going to simplify the radical. To do this, we will apply the product rule of radicals which states that
√(ab)=√(a)*√(b) . In this case:


√(27)=√(9)*√(3)=3√(3)\\\\v-2=\pm\ 3√(3)

Lastly, add both sides by 2:


v=2\pm 3√(3)

Answer:

In exact form, your answer is
v=2\pm 3√(3)

User Kthakore
by
6.0k points
2 votes

Answer:

v = 2 ± 3 sqrt(3)

Explanation:

(v-2)^2-27=0

add 27 to each side

(v-2)^2-27+27=0+27

(v-2)^2 = 27

take the square root of each side , remember to take the positive and negative

sqrt((v-2)^2) = ± sqrt27

v-2 = ± sqrt27

add 2 to each side

v-2+2 = 2 ± sqrt27

v = 2 ± sqrt27

we can simplify the square root of 27

sqrt(27) = sqrt(9) * sqrt(3)

sqrt(27) = 3sqrt(3)

v = 2 ± 3 sqrt(3)


User Sterling Nichols
by
6.1k points