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You are given the following system.x=2y+42x-3y=11 What method would you use to solve this system?

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Answer:

substitution

Explanation:

We assume the two equations are ...

  • x = 2y+4
  • 2x -3y = 11

You are given an expression for x. Using that in the second equation will result in an immediate solution for y.

... 2(2y+4) -3y = 11 . . . . . substituting 2y+4 for x

.. y +8 = 11

... y = 3

... x = 2·3 +4 = 10

The solution is (x, y) = (10, 3)

User Jonathan Holvey
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