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5 votes
Θ lies in Quadrant II .

cosΘ=-
(8)/(11)
What is the exact value of sinθ in simplified form?

User Barns
by
5.5k points

2 Answers

6 votes

Answer:

57√11

Explanation:

User Paul Sachs
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5.1k points
3 votes

Answer:

sin theta = sqrt(57) /11

Explanation:

cos theta = -8/11

cos = opposite/ hypotenuse =x/ (sqrt(x^2+y^2))

sin = adjacent /hypotenuse= y /sqrt (x^2+y^2)


-8/11 = x/ (sqrt(x^2+y^2))

x = -8

sqrt((x^2+y^2)) =11

11^2 = x^2 + y^2

121 = 64+ y^2

57 = y^2

sqrt(57) = y

sin theta = sqrt(57) /11

If it lies in quadrant II

x is negative and y is positive

User Satish Pandey
by
4.9k points