Question

Write an equation of the line that passes through (−3,3) and is perpendicular to the line 2y=8x−6

Answer 1

y-3=-1/8(x+3)

Explanation:

1) Change the given line equation so that y=mx+b

2y=8x-6 (divide both sides by 2)

y=4x-3

2) In y=mx+b form, m is your slope

In this case, that's 4

3) To find a perpendicular line, find the opposite reciprocal

For 8, this is -1/8

4) Put your values into point slope form

x=-3, y=3, m=-1/8

y-y1=m(x-x1)

So you would get y-3=-1/8(x+3) as your final answer :)

Answer 2

the equation of the line: 2y=8x-6

Divide each side by two==>y=4x-3

That means the slope of the line you need to find is -1/4

Using point-slope form, y-3=-1/4(x- -3)

y-3=-1/4(x+3)

y-3=(-1/4x)-(3/4)

y=-1/4x+9/4