Final answer:
To find the equation of a line perpendicular to 2x + 3y = 9 that passes through (-2, 5), we need to find the negative reciprocal of the slope of the given line and use the point-slope form of a linear equation.
Step-by-step explanation:
To find the equation of a line perpendicular to the given line, we need to find the negative reciprocal of the slope of the given line. The given line has the equation 2x + 3y = 9. To get it in slope-intercept form, we can solve for y:
3y = -2x + 9
y = (-2/3)x + 3
The slope of the given line is -2/3. The negative reciprocal of -2/3 is 3/2. So, the slope of the line perpendicular to the given line is 3/2. Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line. The point-slope form is given by:
y - y1 = m(x - x1)
Using the point (-2, 5) and the slope 3/2, we can substitute these values into the equation:
y - 5 = (3/2)(x - (-2))
y - 5 = (3/2)(x + 2)
y - 5 = (3/2)x + 3
y = (3/2)x + 8
Therefore, the equation of the line perpendicular to 2x + 3y = 9 and passing through (-2, 5) is y = (3/2)x + 8.