Answer:
An exponential decay function
where a is the initial value and 0<b<1.
Given the function:
![f(x) = ((3)/(2))^(-x)](https://img.qammunity.org/2019/formulas/mathematics/college/ru4zfmvmgg5x1qookg1qp0qqhwc3aq89wj.png)
or we can write this as;
......[1]
The domain for this function is all real number and the range is, y>0.
also this function is decreasing because b =
< 1.
First find the y-intercept:
y-intercepts defined as the graph crosses the y-axis
substitute x =0 in [1] to find x;
![y = ((2)/(3))^(0) = 1](https://img.qammunity.org/2019/formulas/mathematics/college/hdan89j2otqvra8w0yrgsxuz4bic9neety.png)
y-intercepts: (0, 1).
End behavior of the given function:
- as we increase x, f(x) values grows smaller and approaching to zero i.e,
as
,
![f(x) \rightarrow 0](https://img.qammunity.org/2019/formulas/mathematics/college/caqwabosrahufj8ykhx3pttonrrkhju5lz.png)
- as we decreases s, f(x) grows without bound. i.e,
as
,
![f(x) \rightarrow \infty](https://img.qammunity.org/2019/formulas/mathematics/college/7npw6m0vv08hpto0h0inihx4h7b1pqizy5.png)
As you can see the graph of this function below in the attachment.