Question

at noon a tank contains 10 cm of water after several hours it contains 7 cm of water what is the percent decrease of water in the tank

Answer 1

30%.

Explanation:

We have been given that at noon a tank contains 10 cm of water after several hours it contains 7 cm of water.

To find the decrease percent we will use formula:

`\text{Decrease percent}=\frac{\text{Original value-new value}}{\text{Original value}}* 100`

Upon substituting our given values in above formula we will get,

`\text{Decrease percentage of water in the tank}=(10-7)/(10)* 100`

`\text{Decrease percentage of water in the tank}=(3)/(10)* 100`

`\text{Decrease percentage of water in the tank}=3* 10=30`

Therefore, the percentage decrease of water in the tank is 30%.