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Write an equation parallel to y=2x-3 that contains the point (-2,1)

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4 votes

Answer:

The equation of the parallel line would be y = 2x + 5

Explanation:

To start we need to find the slope of the original line. We can do that by looking at the coefficient of x, which is 2

Since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. Now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 1 = 2(x + 2)

y - 1 = 2x + 4

y = 2x + 5

User Bobbe
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