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A 600 kg elevator starts from rest. It moves upward for 4.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s. (a) What is the average power of the elevator motor during this
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A 600 kg elevator starts from rest. It moves upward for 4.50 s with constant acceleration until it reaches its cruising speed, 1.75 m/s. (a) What is the average power of the elevator motor during this period

User Gaelan
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1 Answer

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Answer:

408.33watts

Step-by-step explanation:

Power is expressed according to the formula

Power = work done/time

Power = force × distance/time

Power = Force× velocity

Find the force

F = mv/t

F = 600×1.75/4.5

F = 1050/4.5

F=233.33N

Get the power

Power = 233.33×1.75

Power = 408.33watts

Hence the average power of the elevator motor during this period is 408.33m/s

User Sdduursma
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