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Fine the slope of a line that passes through (-2,-3) and (1,-1)

User Remjx
by
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2 Answers

1 vote


\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-3)}{1-(-2)}\implies \cfrac{-1+3}{1+2}\implies \cfrac{2}{3}

User Pcsutar
by
5.9k points
1 vote

Answer:

The slope of the line that passes through
(-2, -3) and
(1, -1) is
(2)/(3).

Explanation:

The slope of a line is represented by
(y_(2)-y_(1))/(x_(2)-x_(1)), where the variables are
(x_1, y_1), (x_2, y_2).

Now, we can substitute the variables into the equation.


((-1)-(-3))/(1-(-2))

Now just solve the equation.


((-1)-(-3))/(1-(-2))=(2)/(3)

User Al Polden
by
6.1k points