Question

A helium balloon has a volume of 2.5 L at 274.2 kPa. As the balloon rises the pressure drops to 52.2 kPa. What is the new volume?

Answer 1

According to Boyle's Law, The Volume of an Ideal gas is Inversely proportional to its Absolute Pressure at a Constant Temperature.

`\clubsuit\;\;(p_1)/(p_2) = (v_2)/(v_1)`

Assuming the Helium gas as an Ideal Gas and Temperature of the Atmosphere is Constant :

Here : p₁ = 274.2 kPa and p₂ = 52.2 kPa and v₁ = 2.5

⇒
`(274.2)/(52.2) = (v_2)/(2.5)`

⇒
`v_2 = (274.2*2.5)/(52.2) = 13.13\;L`

So, The New Volume is 13.13 Liter

Answer 2

Hey there, your answer should be 35783.1

The solution was

V= 2.5x274.2x52.2=35783.1

Hope this helped