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How do u solve y-3=2/3(x+5) in standard form

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The standard form:


Ax+By=C

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y-3=(2)/(3)(x+5) multiply both sides by 3


3y-9=2(x+5) use distributive property


3y-9=2x+10 add 9 to both sides


3y=2x+19 subtract 2x from both sides


-2x+3y=19 change the signs


\boxed{2x-3y=-19}

User Katya Mutafchieva
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