Question

the first three terms of the sequence are 6 ,x, y, 27 are terms of an arithmetic sequence, the last three terms of a geometric sequence. fine x and y

Answer 1

x=12

y=18

Explanation:

sequence: 6, x, y, 27

first three are in a arithmetic sequence (constant flow) and last three are in a geometric sequence (increasing flow).

we can put numbers on our x and y to test the sequence.

therefore:

6, 12, 18 are three numbers than increase arithmeticali in 6 units

6+6=12

12+6=18

now the last 3 to proff the geometric increase:

Sequence: 6, 12, 18, 27

12, 18, 27 are in a geometric sequence increased by 3

12+6= 18 now 6+3= 9

18+9=27

the arithmetic sequence is given by 6

the geometric increse is given by an geometric increase of 3