Question

What is the solution to the equation
-3d/d^2-2d-8+3/d-4=-2/d+2?

Answer 1

If im right the answer would be d ≓ -7.366989911

2d3-14d2+5d-3

—————————————— • d2 = 0 • d2

d2

F( -7.366989911 ) is -0.000000096

Answer 2

The solution of the equation is d=1.

Explanation:

Given : Equation
`-(3d)/(d^2-2d-8)+(3)/(d-4)=-(2)/(d+2)`

To find : What is the solution to the equation?

Solution :

Step 1 - Write the equation

`-(3d)/(d^2-2d-8)+(3)/(d-4)=-(2)/(d+2)`

Step 2 - Factor the quadratic equation and take RHS to LHS

`-(3d)/((d+2)(d-4))+(3)/(d-4)+(2)/(d+2)=0`

Step 3 - Take the Least common denominator (LCD)

`(-3d+3(d+2)+2(d-4))/((d+2)(d-4))=0`

Step 4 - Solve the numerator and take denominator to other side

`-3d+3d+6+2d-8=0`

`2d=2`

`d=1`

Therefore, The solution of the equation is d=1.