Question

The probability of students choosing the left lunch line at school is p=0.431. Find the variance of the binomial distribution of 982 students choosing the left lunch line today.

Answer 1

240.8

Explanation:

Answer 2

We are given the probability of students choosing the left lunch line at school is
`p=0.431`

We have to find the variance of the binomial distribution of 982 students choosing the left lunch line today.

Therefore, n = 982

We know that the variance of Binomial distribution is:

`Variance = n * p * (1-p)`

`=982 * 0.431 * (1-0.431)`

`=240.82` rounded to 2 decimal places

Therefore, the variance of the binomial distribution of 982 students choosing the left lunch line today is 240.82