Question

A regulation-sized NBA basketball court measures 94 feet long by 50 feet wide. You are making a scaled drawing of such a court. If you make the length of the court 10 inches, what should you make the width of the court to maintain the proper proportions in your drawing? Round your answer to two decimal places.

The width of the court needs to be __________ inches to maintain proper proportions.

Answer 1

About 5.32 inches

Explanation:

94 ft = 1,128 in.

1,128 / 112.8 = 10

So if you want to balance it, multiply 50 by 12 to get 600 inches which is equivalent to 50 feet.

600 / 112.8 = about 5.32 inches

Answer 2

The width of the court needs to be 5.32 inches to maintain proper proportions.

Explanation:

Consider the provided information.

A regulation-sized NBA basketball court measures 94 feet long by 50 feet wide.

We make the length of court 10 inches. Now let us convert 94 feet in the ratio of 10 inches. We can convert 94 feet into 10 inches by dividing the number 94 with 9.4

Therefore

`(94)/(9.4)=10\ inches`

Thus, divide 50 feet with 9.4 feet. So that you can maintain proper proportion in drawing.

`(50)/(9.4)=5.32\ inches`

Hence, the width of the court needs to be 5.32 inches to maintain proper proportions.