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What is the area of a triangle with vertices at (−2, -3) , (6, -3) , and (2, 5) ?

User Xiao Luo
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Hello from MrBillDoesMath!

Answer : 32

Discussion:

Label the points as follows:

A = (-2, -3), B = ( 6, -3), C = ( 2.5)


Area of a triangle = (1/2) bh

where "b" is the "base" and "h" is the height of the triangle.

In our case, the base is the line AB, so the length of the base is

b = 6 - ( -2) = 6 + 2 = 8

(6 and -2 are the x coordinates of the points B and A, respectively)


The height is the distance from the y-coordinate of point C to the base AB. That is,

5 - (-3) = 5 + 3 = 8

(5 is the y coordinate of point C; -3 is the y coordinate of the line AB)


Finally,

Area = (1/2) * 8 * 8 = (1/2) 64 = 32



Thank you,

MrB

User Alon Alush
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