Answer:- 6
Solution:- The given hypothetical equation is:
![3A+3B\rightarrow 6C](https://img.qammunity.org/2019/formulas/chemistry/high-school/zg7pii0c0sli269zlqtq81kj0aifj50i6u.png)
From this equation, there is 3:6 mol ratio between A and C.
From given info, 3 moles of A reacts with excess of B to produced C. It asks, how many moles of C are produced.
Since the mol ratio between A and C is 3:6 means 3 moles of A produce 6 moles of C.
We multiply the given number of moles of A by the mol ratio.
So,
![3molA((6molC)/(3molA))](https://img.qammunity.org/2019/formulas/chemistry/high-school/su32xj2prv7scngsvr5sjchlvsly1x9s68.png)
= 6 mol C
It wants answer without the unit. So, the answer is 6.