Question

For the following hypothetical reaction:

3A+3B-->6C.

How many moles of C can produce with 3 moles of A and excess B?

(Enter just the number: not the number and units) Your answer

Answer 1

Answer:- 6

Solution:- The given hypothetical equation is:

`3A+3B\rightarrow 6C`

From this equation, there is 3:6 mol ratio between A and C.

From given info, 3 moles of A reacts with excess of B to produced C. It asks, how many moles of C are produced.

Since the mol ratio between A and C is 3:6 means 3 moles of A produce 6 moles of C.

We multiply the given number of moles of A by the mol ratio.

So,

`3molA((6molC)/(3molA))`

= 6 mol C

It wants answer without the unit. So, the answer is 6.